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(5x-4)/(x^2-3)=0
Domain of the equation: (x^2-3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x^2!=3
x^2!=3/
x^2!=√1/0
x!=1
x∈R
(5x-4)=0
We get rid of parentheses
5x-4=0
We move all terms containing x to the left, all other terms to the right
5x=4
x=4/5
x=4/5
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